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models/issue.go NewIssue() could fail due to duplicate key #3796
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opened 2025-11-02 05:25:30 -06:00 by GiteaMirror
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Reference: github-starred/gitea#3796
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Originally created by @guillep2k on GitHub (Aug 16, 2019).
The current code for
models/issue.goroughly does:It's possible that under heavy loads (e.g. a small server) two sessions may attempt to use the same index number to create issues; one of the two will fail due to a race condition:
issue.go, in the context of user A's request,getMaxIndexOfIssue()returns99. It will be used at step 5.issue.go, in the context of user B's request,getMaxIndexOfIssue()also returns99. because at the moment that's the latest issue for the repo. It will be used at step 6.issue.go, in the context of user A's request,newIssue()inserts A's issue withIndex: 100.issue.go, in the context of user B's request,newIssue()attempts to insert B's issue withIndex: 100and fails withduplicate key error, because100was used at step 5.This will of course depend on the database locking model.
I think the best way to handle this is to use a mutex, thus covering most scenarios.
@zeripath commented on GitHub (Aug 17, 2019):
So a mutex would actually be at the wrong level - it needs to be at the DB level (Consider clusters). There's only really three options to fix it:
I think option 1 is probably a reasonable thing to do, but someone with more specific DB knowledge could look into how much work it would be to add 2 or 3 - but I think you still need retries when I last looked into this.
@lunny commented on GitHub (Aug 17, 2019):
If we want finish that on DB level, it's a complex SQL and specific for different databases. So I think the simple and dirty method is just retry it 3 times if it failed because of exist issue number.
@typeless commented on GitHub (Aug 28, 2019):
Ultimately, I would like to consider dropping the
indexcolumn from the table. It should be something deducible from the other columns.@lunny commented on GitHub (Oct 1, 2019):
This should be resolved by #8309@guillep2k commented on GitHub (Oct 1, 2019):
Unfortunately, it won't. Consider the following scenario:
By the time T2 inserts the row in
issueusingMAX(index), T1 already picked the value3for that, but T2 can't possible know about it because T1 didn't commit the changes yet. So T2 also picks the value3and fails at the time of the commit.I realized this when I created the stress test in #8005. It will always fail with this kind of method, unless we use some method of serialization like a semaphore or a lock in the table. But the semaphore will not scale in a multi-server setup as you've pointed out, and a database lock (either at row or table level) is dangerous because it's very easy to end up with a deadlock.
That's why I gave up and went for the retry route.